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OpenStudy (tamara7301):
OpenStudy (br5ttany):
-3/5
OpenStudy (tamara7301):
thx
imqwerty (imqwerty):
its 5/3
OpenStudy (br5ttany):
Wait its 5/3
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imqwerty (imqwerty):
(:
OpenStudy (br5ttany):
XD you were faster
imqwerty (imqwerty):
tama did u get how to solve it?
OpenStudy (tamara7301):
no :(
imqwerty (imqwerty):
ok 1st we have this->\[\frac{ 3 }{ 5 }x =12\]
and finally we have this->\[x=20\]
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imqwerty (imqwerty):
so basically the x is being isolated
ok?
imqwerty (imqwerty):
to isolate x the 3/5 has to be removed
OpenStudy (br5ttany):
If you multiply 3/5 and 12 by 5/3 then you get 1 and 20, making the equation 1X=20 which is the same as X=20
OpenStudy (tamara7301):
yea
imqwerty (imqwerty):
can u think of a way to remove the 3/5
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OpenStudy (tamara7301):
subtract?
imqwerty (imqwerty):
no
OpenStudy (tamara7301):
:( y not
imqwerty (imqwerty):
if we subtract any term say T it will be like this-\[\frac{ 3 }{ 5 }x-T=12-
T\]and when we will simplify it further it will go like this-\[\frac{ 3x-T(5) }{ 5 }=12-T\]what do u think..is subtraction making things more easy or complicated?
is x likely to get isolated this way?
OpenStudy (tamara7301):
OH
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imqwerty (imqwerty):
so do u think subtraction will work?
OpenStudy (tamara7301):
no
imqwerty (imqwerty):
ok now we try multiplication :)
imqwerty (imqwerty):
do u agree to the fact that\[a \times \frac{ 1 }{ a }=1\]?
OpenStudy (tamara7301):
ok
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imqwerty (imqwerty):
we know that \[a \times 1=a\]
so \[\frac{ a \times 1 }{ a }=\frac{ a }{ a }\]
OpenStudy (tamara7301):
yup
imqwerty (imqwerty):
overall till now we've done this-\[a \times \frac{ 1 }{ a }=\frac{ a \times 1 }{ a }=\frac{ a }{ a }\]
now what do u think is the value of\[\frac{ a }{ a }=?\]
OpenStudy (tamara7301):
1
OpenStudy (tamara7301):
wait nvm its a
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imqwerty (imqwerty):
no no
its 1
OpenStudy (tamara7301):
really isnt supposed to be a cause they r both a's
imqwerty (imqwerty):
ok lets take an example
lets assume a to be 2
OpenStudy (tamara7301):
lol
imqwerty (imqwerty):
what do u think is the value of \[\frac{ 2 }{ 2 }\] is it 2?
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OpenStudy (tamara7301):
no its 1 cause they get a whole num of 1
imqwerty (imqwerty):
yes
so now what do u think is the value of\[\frac{ a }{ a }\]
OpenStudy (tamara7301):
1
imqwerty (imqwerty):
yea
OpenStudy (tamara7301):
:)
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imqwerty (imqwerty):
so now we have this-\[\frac{ 3 }{ 5 }x=12\]
we need to isolate x
and ofc we have to use multiplication its written in the ques
OpenStudy (tamara7301):
oh ok
OpenStudy (tamara7301):
yupppppppppppppppppppppp
OpenStudy (tamara7301):
i understand now
imqwerty (imqwerty):
ok so what will u do next :)
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OpenStudy (tamara7301):
u switch them to 5/3
OpenStudy (tamara7301):
then u multiply 5/3 with 20
OpenStudy (tamara7301):
jk
OpenStudy (tamara7301):
i meant 12
OpenStudy (tamara7301):
thats how u get 20
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OpenStudy (tamara7301):
right?
imqwerty (imqwerty):
yes :)
OpenStudy (tamara7301):
yay is it ok if u help me with more or r u busy
imqwerty (imqwerty):
yea i can help
OpenStudy (tamara7301):
yay ok
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OpenStudy (tamara7301):
imqwerty (imqwerty):
did u try to do this one?
OpenStudy (tamara7301):
yea but i dont understand it
OpenStudy (tamara7301):
cause theres no answer to see if its right or not idk
imqwerty (imqwerty):
ok :)
do u understand the concept of |x| ?
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OpenStudy (tamara7301):
yup
OpenStudy (tamara7301):
that means like the exact
like if i had 12 then i would have to have a -12
imqwerty (imqwerty):
no
its like u will always get a positive of the number\[|12|=12\]\[|-12|=12\]ok?
OpenStudy (tamara7301):
yea i mean i guess thats what i meant
imqwerty (imqwerty):
ok so we can say that whenever we have something like |x| it will always be positive
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OpenStudy (tamara7301):
lol
OpenStudy (tamara7301):
yuppppp
imqwerty (imqwerty):
ok now u tell this-
If I say that \[|x|=-3\]what will u say
OpenStudy (tamara7301):
ugh qwerty u made it difficult>.<
i think thats it would be -3 and 3 cause the teacher tells us we have to choose 2 num
OpenStudy (tamara7301):
:( u left
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imqwerty (imqwerty):
no m still here
OpenStudy (tamara7301):
ok :)
imqwerty (imqwerty):
(:
we just said that if u have anything like this->
|x| then it will always give something positive\[|x|=SomethingPositive\]
imqwerty (imqwerty):
what your teacher must have said is this->
for example if ur given\[|x|=7\]then x can be 7 or -7 because\[|7|=7\]and\[|-7|=7\]
OpenStudy (tamara7301):
yea
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imqwerty (imqwerty):
ok so i asked u something-
what will u say if i tell u that\[|x|=-3\]
OpenStudy (tamara7301):
l-3l=3
OpenStudy (tamara7301):
right?
imqwerty (imqwerty):
(:
imqwerty (imqwerty):
well we know that\[|x|=SomethingPositive\]but here\[|x|=-3\]
-3 is negative so there is no such value of x that will satisfy the equation
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OpenStudy (tamara7301):
oh
OpenStudy (tamara7301):
@rhettwalker14
OpenStudy (anonymous):
i suck at math
imqwerty (imqwerty):
the |x| always gives out the positive value
this is its wrk
it can never give something negative
so |x|=-3 is not possible
so no solutions
imqwerty (imqwerty):
ok?
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OpenStudy (anonymous):
i dont get it
imqwerty (imqwerty):
which part?
and @Tamara7301 ??
OpenStudy (tamara7301):
yes
imqwerty (imqwerty):
so now we move towards solving the questions
imqwerty (imqwerty):
1st u try to isolate the |x|
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