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2(3)^x=3^x+3 x=-1 x=0 x=1 x=6 I think A or C
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I'm sorry,idk ;( I'm only in 6th grade :'(
I don't know. I am not that smart!
ok
thanks anyways
@Michele_Laino
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If I subtract \(3^x\) from both sides, I get: \[\huge 2 \cdot {3^x} - {3^x} = {3^x} + 3 - {3^x}\] please simplify
hint: we have: \[\huge 2 \cdot {3^x} - {3^x} = \left( {2 - 1} \right){3^x} = ...\]
2=3^x
what is \(2-1\)?
1
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correct! So, left side can be rewritten as follows: \[\huge 2 \cdot {3^x} - {3^x} = \left( {2 - 1} \right){3^x} = {3^x}\]
so x could just equal 1?
therefore, the equation, can be rewritten like below: \[\huge {3^x} = {3^1}\]
correct! The solution is \(x=1\)
ok thanks so much once again
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