Which of the following represents the graph of f(x) = 3x2 - 12 ?
@Michele_Laino
from your equation, I get: \(f(0)=-12\), so the correct graph has to pass at point \((0,-12)\)
what are your options, please?
There are 3 that do..
more precisely, the equation \(f(x)=3x^2-12\), is a parabola, which is concave up
The first one lands on -2 and 2
The next one lands on -3 and 3
And the last one lands on -4 and 4
If I replace \(x=2\) I get: \(f(2)=3 \cdot 2^2-12=...?\)
please complete that computation
0?
3x4 is 12 - 12 is 0.
correct! Similarly, if I rplace \(x=-2\), I get: \(f(-2)=3 \cdot (-2)^2-12=...?\)
replace*
Wouldn't that be 0 too?
correct!
So how do I figure out which graph is right?
so, summarizing, we have these 3 conditions: 1) the parabola passes at point \((0,-12)\) 2) the parabola passes at point \((2,0)\) 3) the parabola passes at point \((-2,0)\) |dw:1447696487976:dw|
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