Which of the following represents the vertical asymptotes of the function f(x)= x/ x^2 - 2x - 8 ?
@Michele_Laino
A. x = -8 and x =1 B. x= -1 and x = 8 C. x = -4 and x = 2 D. x = -2 and x = 4 Those are my choices.
vertical asymptotes are positioned at values of \(x\), such that the denominator is equal to zero, so, we have to solve this quadratic equation: \(\huge x^2-2x-8=0\)
How do I do that?
do you know how to solve a quadratic equation?
no..):
in that case, we can solve such equation, in another way, namely, you have to search, among your options, two numbers, such that their product is equal to \(-8\), and their sum is equal to \(2\)
Like out of my choices?
for example, first option gives, -8, and 1, now: sum = -8+1= -7 which is different from 2, so option A, is a wrong option
I say C.
D*
I think C is wrong since we have -4, and 2, and: sum = -4+2=-2 which is different from 2
option D is the correct option! :)
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