I need help fast.
3 ≤ x over -2
A) x ≥ -6 B) x ≥ -1 C) x ≤ -1 D) x ≤ -6
Does anyone know how to do this?
@alex Can you help me solve this?
\[\large\rm 3\le \frac{x}{-2}\]We want to isolate our x. Think of the fraction as `division`. So how do you undo the division by -2? Which operation?
subtract 2 from each side?
Hmm, no. We could `undo addition` with subtraction. But that's not how we undo division. That's not the opposite.
Multiply
Ok good, let's multiply both sides by -2 to `undo` the division by -2. Do you remember what happens when you multiply or divide a `negative across an inequality`?
Noo
one side would be -6
Yes :) one of the sides is -6. \[\large\rm 3\color{orangered}{\le} \frac{x}{-2}\] \[\large\rm -2\cdot3\color{orangered}{\ge} \frac{x}{-2}\cdot-2\]When you multiply or divide a negative across the inequality, the sign flips.\[\large\rm -2\cdot3\color{orangered}{\ge} x\]
Yess
So now what? :3
I think that's it, right? 0_o\[\large\rm -6\color{orangered}{\ge} x\]Multiplying the -2 and 3 gave you -6. Just make sure you have the inequality facing the correct way, as I've show here.
Oh, in the answer key, they have the x's on the left side. That might be a little confusing.
so in the answer key it would be D ? :) ps:Thank you! You're explanation was perfect!
@AlexandervonHumboldt2
\(\rm -6\ge x\) is the same as \(\rm x\le-6\). Yes, good job \c:/
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