Check my answer.. I believe its 2 months
Two separate bacteria populations grow each month and are represented by the functions f(x) = 3x and g(x) = 7x + 6. In what month is the f(x) population greater than the g(x) population? Month 1 Month 2 Month 3 Month 4
so f(x) = 3x if x= 2 what is 3x? g(x) = 7x+ 6 if x=2 what is 7x + 6 so 2 is not the right answer I think you must have written it wrong because for positive counts of the months 7x+6 is always greater than 3x
@MrNood ohh okay. Would it be 3 months? eh
I think you must have written it wrong because for positive counts of the months 7x+6 is always greater than 3x
I think you must have written THE QUESTION wrong because for positive counts of the months 7x+6 is always greater than 3x
@MrNood No.. I just copied and pasted it into the question box
well - look at it if x is positive then 7x is ALWAYS going to be > 3x (even before you add 6) None of those answers is correct - so the question must be wrong are you sure it's not 7x-6?
One sec.. Maybe some other math words got mixed in.
Here is the question: Two separate bacteria populations grow each month and are represented by the functions f(x) = 3x and g(x) = 7x + 6. In what month is the f(x) population greater than the g(x) population?
if x is positive then 7x is ALWAYS going to be > 3x (even before you add 6) None of those answers is correct
@MrNood hm I see what you mean
most population growth question involve 'exponential' are you sure that the copy has not missed out some formatting eg \[3^{x}\]
@MrNood I am pretty sure
@celinegirl please post a screenshot of the full problem. There may be something missing but I'm not sure
Okay... here:
Thanks
Ok so f(x) isn't 3x it's 3^x
if you plug in x = 2 into f(x) = 3^x, what do you get?
@jim_thompson5910 9?
Aha - as I suspected! :-) Now work out f(x) for x = 2, 3 and 4 then work out g(x) for x = 1,2,3,4 you will see when it is GREATER than g(x)
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