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OpenStudy (chris215):
If f(x) = 9x10 tan-1x, find f '(x).
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OpenStudy (chris215):
I got 90x^9tan^-1x + 9x^10 1/1+x^2
HanAkoSolo (jamierox4ev3r):
hmm.. I'm not sure if I'm completely clear on your notation. is this your function?
\(\Large f(x)=9x10 tan(-1x)\)
or
\(\Large f(x)=9x10tan(x)-1x\)
OpenStudy (chris215):
opps sorry its f(x) = 9x^10 tan^-1x
OpenStudy (misty1212):
HI!!
OpenStudy (chris215):
hi :)
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OpenStudy (misty1212):
it is a product, you need to use the product rule
OpenStudy (misty1212):
\[\left(fg\right)'=f'g+g'f\] with \[f(x)=9x^{10},f'(x)=90x^8,g(x)=\tan^{-1}(x), g'(x)=\frac{1}{1+x^2}\]
HanAkoSolo (jamierox4ev3r):
There is also an instance of chain rule that you have to take into account when using the product rule for this particular derivation
OpenStudy (misty1212):
oh i didn't even see your answer! it is right !!
OpenStudy (chris215):
oh ok thank you!!
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OpenStudy (misty1212):
\[\color\magenta\heartsuit\]
HanAkoSolo (jamierox4ev3r):
lol @misty1212 , well done breaking down the product rule! I think that was very well explained ^_^
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