If f(x) = 9x10 tan-1x, find f '(x).
I got 90x^9tan^-1x + 9x^10 1/1+x^2
hmm.. I'm not sure if I'm completely clear on your notation. is this your function? \(\Large f(x)=9x10 tan(-1x)\) or \(\Large f(x)=9x10tan(x)-1x\)
opps sorry its f(x) = 9x^10 tan^-1x
HI!!
hi :)
it is a product, you need to use the product rule
\[\left(fg\right)'=f'g+g'f\] with \[f(x)=9x^{10},f'(x)=90x^8,g(x)=\tan^{-1}(x), g'(x)=\frac{1}{1+x^2}\]
There is also an instance of chain rule that you have to take into account when using the product rule for this particular derivation
oh i didn't even see your answer! it is right !!
oh ok thank you!!
\[\color\magenta\heartsuit\]
lol @misty1212 , well done breaking down the product rule! I think that was very well explained ^_^
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