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*Trigonometric Functions* Consider the equation 3tan2(x)−1=0. The solutions of this equation over the interval [0, π] are? *Please help will give medal*
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solve \[\tan(x)=\pm\frac{1}{\sqrt{3}}\]
x=π6±πn,7π6±πn
Is that correct?
yeah i guess \(\frac{\pi}{6}\) works for sure
yeah that looks good except it said only on the interval \[[0,\pi]\]
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what about the second one?
you have a general solution there you only want the solution on \([0,\pi]\) not a general one
ok so can you help me with getting that?
sure
\[\frac{\pi}{6}\] works because \[\tan(\frac{\pi}{6})=\frac{1}{\sqrt3}\] do you know why (just asking)
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because you subtracted it?
the other one on that interval is \(\frac{5\pi}{6}\)
Okay thanks so much! I appreciate it I got it now.
yw
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