Question

*Trigonometric Functions*
Consider the equation 3tan2(x)−1=0.
The solutions of this equation over the interval [0, π] are?
*Please help will give medal*

Answer 1

solve \[\tan(x)=\pm\frac{1}{\sqrt{3}}\]

Answer 2

x=π6±πn,7π6±πn

Answer 3

Is that correct?

Answer 4

yeah i guess
\(\frac{\pi}{6}\) works for sure

Answer 5

yeah that looks good except it said only on the interval \[[0,\pi]\]

Answer 6

what about the second one?

Answer 7

you have a general solution there
you only want the solution on \([0,\pi]\) not a general one

Answer 8

ok so can you help me with getting that?

Answer 9

sure

Answer 10

\[\frac{\pi}{6}\] works because \[\tan(\frac{\pi}{6})=\frac{1}{\sqrt3}\]
do you know why (just asking)

Answer 11

because you subtracted it?

Answer 12

the other one on that interval is \(\frac{5\pi}{6}\)

Answer 13

Okay thanks so much! I appreciate it I got it now.

Answer 14

yw