Question

critical points of x-15x^(1/3)

Answer 1

set \[1-\frac{5}{\sqrt[3]{x^2}}=0\] and solve

Answer 2

also since the derivative is undefined if \(x=0\) you have \(0\) as a critical point as well

Answer 3

i'm not getting it right

Answer 4

are you stuck at solving for \(x\)?

Answer 5

or at finding the derivative?

Answer 6

solving for x

Answer 7

then you are thinking way too hard
take two steps
or three

Answer 8

\[1-\frac{5}{\sqrt[3]{x^2}}=0\\
\frac{5}{\sqrt[3]{x^2}}=1\\
\sqrt[3]{x^2}=5\] is a start

Answer 9

yeah, I get that far

Answer 10

oh then if \[\sqrt[3]{x^2}=5\] you have \[x=\sqrt{5^3}\]

Answer 11

yeah, that's what I thought but its saying its wrong

Answer 12

it is right

Answer 13

also 0

Answer 14

I put both and says that it is wrong. That's why I am so lost about it

Answer 15

hmm i think it is right
maybe it wants a decimal? maybe it wants a decimal to more places?
can you post a screenshot?

Answer 16

hmm i don't see the instructions, but i am lost
pretty positive the answer is right

Answer 17

unless for some reason they want you to write \[5\sqrt5\] but that is awful picky

Answer 18

that isn't right either

Answer 19

I figured it out. it was 0, 5sqrt5 and -5sqrt5