Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (amonoconnor):

I'm encountering a sign issue in what I think is a pretty simple problem... Would someone be willing to take a look, and show me what I'm doing wrong? The problem: "Evaluate: (integral)[(v^2 + 3v^6)/v^4]dv, from 1 to 2." Any and all help is greatly appreciated!

OpenStudy (amonoconnor):

Here's what I did: \[f(v) = \frac{v^2 + 3v^6}{v^4}\] = \[f(v) = \frac{v^2 + 3v^6}{v^4} = \frac{3v^4 + 1}{v^2}\] \[= (3v^4 + 1)v^{-2}\] \[= 3v^2 + v^{-2}\] \[F(v) = v^3 + (-v^{-1})\] \[= v^3 - \frac{1}{v} \]

OpenStudy (anonymous):

looks good to me

OpenStudy (amonoconnor):

Now here is where I genuinely kind of kind don't understand what my book does. The final answer is: ln(2) + 7, meaning that F(b) must have a ln(2) in it. The obvious thing in that the v^(-1) is substituted by a ln(v), but wouldn't the v^(-1) have to be in f(v), not a term in F(v), for that to happen? The DERIVATIVE of ln(v) = 1/v, but they're not equal in and of themselves, so why is a ln(v) showing up in the evaluation if there isn't a 1/v in the function –> f(v) –> 3v^2 + v^(-2) ??

OpenStudy (amonoconnor):

Well, I took the book at its work, and went ahead plugging in a "ln(v)" for v^(-1), and got the following at the end, after doing this...

OpenStudy (anonymous):

there is no log in the answer

OpenStudy (anonymous):

maybe it is a typo in the question, or you are looking at the wrong answer the only way for there to be a log is if you had \(\frac{1}{v}\) in the integrand

OpenStudy (amonoconnor):

\[= F(b) - F(a)\] \[[(2^3) - \ln(2)] - [(1^3)-\ln(1)]\] \[(8-\ln(2)) - (1)\] \[7 - \ln(2)\]

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

http://www.wolframalpha.com/input/?i=integral+1+to+2++ \frac{v^2+%2B+3v^6}{v^4}

OpenStudy (anonymous):

don't think any more about it it is wrong that is all

OpenStudy (amonoconnor):

I totally agree @satellite73 !! I've double, and triple checked that I've written down the right problem and am looking at the right answer, and even checked the answer on wolframalpha (they say 15/2 which is darn close to [ln(2) + 7] in a calculator. I don't know what I did wrong, but my book has 7 PLUS ln(2), and I got 7 MINUS ln(2) .... :/

OpenStudy (anonymous):

it happens and people get bend out of shape because they believe the book as to be right so they must have screwed up somewheres think no more about it the answer is 7.5

OpenStudy (anonymous):

the question was not written by god or even a mathematician neither were the answers they are written by impoverished graduate students exhausted from a diet of ramen noodles and discount beer

OpenStudy (amonoconnor):

When I say screw the book's "ln(v)" I get 7.5 exactly as well. Thank you so much!!!

OpenStudy (amonoconnor):

Bahahaha!!! I love that reality check–– made my night;)

OpenStudy (anonymous):

now forget about it

OpenStudy (zarkon):

I had the ramen noodles ... I skipped the discount beer

OpenStudy (anonymous):

add soy sauce, hot sauce to splurge

OpenStudy (anonymous):

to the noodles and the beer

OpenStudy (amonoconnor):

You guys are the best;) Thanks again!

OpenStudy (shadowlegendx):

ramen noodles and discount beer, LOL

OpenStudy (amonoconnor):

I'm more of a ricaroni and cheep vodka kind of guy...

OpenStudy (shadowlegendx):

Glad to know not all the mods are robots, love the sarcasm ;p

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!