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f(x)= x^2 In x = 2x Inx + x^2 (1) = x(2 Inx+1)
Is it right??
not quite you have used the product rule correctly by if f(x) = ln(x) then f'(x) = 1/x so in the 2nd part of the dervative you should have \[x^2 \times \frac{1}{x}\] now simplify this
Interestingly enough, it's like that is what he did...but wrote it incorrectly up there Because yes the second part becomes just x And via factoring out the 'x' at the end you arrive at the result originally written above
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