Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (baru):
is that what you got?
OpenStudy (mtalhahassan2):
yes i got the same thing but are you not missing -1
OpenStudy (baru):
see the second term: i have written (- x)
OpenStudy (mtalhahassan2):
oh ok so you put the -1 inside the backet
OpenStudy (baru):
yes
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (mtalhahassan2):
wait at the back of the book they have different answer i guess they simplify further
OpenStudy (baru):
[y=\frac{e^x}{x}-\frac{e^x}{x^2} \]
imqwerty (imqwerty):
lol finally!!!
some life detected on os
OpenStudy (baru):
\[y=\frac{e^x}{x}-\frac{e^x}{x^2} \]
OpenStudy (baru):
just take LCM
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (baru):
yeah, things have become really quiet qwerty
imqwerty (imqwerty):
yes its too quiet :)
i do research wrk on os when its quiet like this
OpenStudy (baru):
lol...research?? i'm suspicious O.o
OpenStudy (baru):
@MTALHAHASSAN2
your answer matched with textbook?
imqwerty (imqwerty):
yes
my current project is to make a blank username..i can make it tho but only if the character->"%" was allowed ): but its not
m wrkin on finding ip's of diff ppl e.e
i've found 10so far
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (mtalhahassan2):
no they are getting like y1= e^x / x^2 (x-1)
OpenStudy (baru):
like i said, just take common denominator
\[y=\frac{xe^x}{x^2}-\frac{e^x}{x^2} \]
OpenStudy (baru):
take e^x/x^2 common
OpenStudy (mtalhahassan2):
i goted that but how they are getting (x-1)
OpenStudy (baru):
taking \(e^x/x^2\) common
\[y=\frac{e^x}{x^2}(x-1)\]
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (baru):
@MTALHAHASSAN2
OpenStudy (mtalhahassan2):
So this is what we got right?? y= e^x (x^-1) + e^x (-x^-2)
OpenStudy (mtalhahassan2):
e^x be the commom
OpenStudy (baru):
yes
OpenStudy (mtalhahassan2):
I am confuse
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (mtalhahassan2):
know how can we solve
OpenStudy (baru):
you know this right:
\(x^{-1}=\frac{1}{x}\)
OpenStudy (mtalhahassan2):
yes
OpenStudy (baru):
wait website hanging
OpenStudy (mtalhahassan2):
can you help me with y= log 10 (1-x+x^3)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (astrophysics):
Hint:\[\frac{ d }{ dx }\log_ax =\frac{ 1 }{ xlna }\]
OpenStudy (unklerhaukus):
\[y= \frac{e^x}x\]
With the quotient rule
\[y' =\frac{xe^x-e^x}{x^2}\]
factoring the numerator
\[=\frac{(x-1)e^x}{x^2}\]