http://prntscr.com/93q1vo
@Directrix
hint: if \(a>b\) then we have \(a/b>1\), so we can write: \[\huge {3^{\frac{a}{b}}} > {3^1}\]
hint: In general, we can write: \[\huge \sqrt[n]{{{x^m}}} = {x^{\frac{m}{n}}}\]
is the first option correct as well?
yes! first option is a correct option
thnx
:)
I agree that the first option is correct by definition of the radical meaning of 3^(a/b).
Nowhere is it said in the problem that a and b are positive Consider 3 ^( (0/(-1) ) = 3^0 = 1. 0 > -1 but 3^ (a/b) < 3 Also, -3>-4 but 3^ ( (-3) / (-4) ) = 3^(3/4) which is also less than 3. For that reason, I would rule out options B and C. Option D is obviously wrong if option A is correct. Bottom Line: Option A is the only correct answer. @Diana.xL I suggest you get a third opinion before submitting an answer to this.
ok thnx
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