a.) The following reaction takes place in an acidic
solution
MnO4-(aq) + Cl-(aq) -- Mn^2+ +Cl2(g)(unbalanced)
i.) Write the reduction and oxidation half-reactions(without electrons)
ii.) Balance the equations for atoms O and H using H2O and H+
iii.)Balance the charge in the half reactions
iv.) Balance the charge in the half reactions
v.) Multiply each half-reaction by the proper number to balance charges in the reaction
vi.) Add the equations and simplify to get a balanced equation.

Question

a.) The following reaction takes place in an acidic 
solution
MnO4-(aq) + Cl-(aq) --> Mn^2+ +Cl2(g)(unbalanced)
i.) Write the reduction and oxidation half-reactions(without electrons)
ii.) Balance the equations for atoms O and H using H2O and H+
iii.)Balance the charge in the half reactions
iv.) Balance the charge in the half reactions
v.) Multiply each half-reaction by the proper number to balance charges in the reaction
vi.) Add the equations and simplify to get a balanced equation.

anonymous · Answer

Use the acronym OIL-RIG, which stands for Oxidation Is the Loss of electrons and Reduction Is Gain of electrons.

Are you sure the given equation is not miscopied?

msambergrace · Answer

I guess the equation should
 MnO4-(aq) + Cl-(aq) --> MnO2+ +Cl2(g)
And the answer Wud be the
2MnO4-(aq) + 6Cl-(aq) + 8H+ --> 2MnO2+ 3Cl2(g) + 4H2O