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Mathematics 73 Online
OpenStudy (atomicreaper):

The center of a circle is located at (3, 8), and the circle has a radius that is 5 units long. What is the general form of the equation for the circle? x2 + y2 − 6x − 16y + 48 = 0 x2 + y2 − 6x − 16y − 25 = 0 x2 + y2 + 6x + 16y + 48 = 0 x2 + y2 + 6x + 16y − 25 = 0

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