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OpenStudy (error1603):
How do I find the inverse function of this, and check my answer?
I need a detailed explanation please
OpenStudy (error1603):
OpenStudy (brooke2353):
well first what are the steps for finding an inverse operation??
OpenStudy (error1603):
umm
OpenStudy (brooke2353):
1. First, replace with y. This is done to make the rest of the process easier.
2. Replace every x with a y and replace every y with an x.
3. Solve the equation from Step 2 for y. ...
4. Replace y with . ...
5. Verify your work by checking that and are both true.
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OpenStudy (error1603):
x = (y^2 + 3)/(3y^2)
OpenStudy (brooke2353):
there you go
OpenStudy (error1603):
So thats it?
OpenStudy (brooke2353):
yeah thats the steps to solving that equation
so lets say..
Here's how the process works:
Here's my original function:
y = 3x - 2
Now I'll try to solve for "x =":
y + 2 = 3x
(y + 2)/3 = x
Once I have "x =", I'll switch x and y; the "y =" is the inverse.
y = (x + 2)/3
OpenStudy (error1603):
then x=2 gives y=7/12
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OpenStudy (brooke2353):
perfect
OpenStudy (error1603):
so sub x=7/12 into y=sqrt(3/(3x-1)
OpenStudy (brooke2353):
uhhh... what?
OpenStudy (brooke2353):
oh okay my bad i was lost for a second
OpenStudy (error1603):
Wait im lost
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OpenStudy (brooke2353):
lol i forgot to plug the square rool into the equation you were right
OpenStudy (error1603):
sub x=(1/3 + 1/x^2) into
sqrt(3/(3x-1)?
OpenStudy (brooke2353):
yup
OpenStudy (brooke2353):
and then so forth
OpenStudy (error1603):
So f^-1(x) = √(3/(3x-1))
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