Question

*Trigonometric Identities*
Given tan(x)=1/3 and cos x < 0, find the value of cos(x)?
*Will fan and give medal*

Answer 1

help por favor

Answer 2

You can use
Sec^2 x =1+tan^2 x
Then put sec^2 x=1/(cos^2 x)

Answer 3

Is that the answer?

Answer 4

Its Hint

Answer 5

I don't know how to do it

Answer 6

Is answer {-3/√10}

Answer 7

is that the answer @Pawanyadav

Answer 8

GRACIAS

Answer 9

Use above identity
Put tan x=1/3
Sec ^2 x= 1+(1/3)^2
I/(cos^2 x)=10/9
So cos^2 x=9/10
Then cos x<0
So cos x=- √{9/10}=-3/√10

Answer 10

What is sec(x)?

Answer 11

1/cos x=sec x=-(√10)/3

Answer 12

Thank you so much

Answer 13

Welcome