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Chemistry 16 Online
OpenStudy (anonymous):

PLEASE HELP! I'M NOT THAT GOOD AT CHEMISTRY AND I REALLY NEED TO PAST THIS. 1. You have three elements, A, B, and C, with the following electronegativity values: A = 0.9 B = 3.0 C = 3.5 You react the elements to form the substances AB, AC, and BC. Answer the following questions: • What type of substance is AB? What types of bonds are present? Explain your answer. • What type of substance is AC? What types of bonds are present? Explain your answer. • What type of substance is BC? What types of bonds are present? Explain your answer. • If any of the substances are ionic compounds,

OpenStudy (anonymous):

which element is the cation and which is the anion? Explain your answer.

OpenStudy (anonymous):

@Whitemonsterbunny17 Can you help me please?

OpenStudy (anonymous):

AB is most likely a covalent and polar substance, because it contains polar covalent bonds. (The difference in electronegativity, 1.1 (3.0-.9), is in the range for polar covalent bonds). I think the range is about .4 to 1.7, with less than .4 being non-polar covalent and greater than 1.7 being ionic. Keep in mind that geometry affects polarity. So with the other questions, consider the difference in electronegativity between the 2 bonded substances and where that falls in the range.

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