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Mathematics 7 Online
OpenStudy (anonymous):

Need help studying Polar/Cartesian forms and Trigonometric form

OpenStudy (anonymous):

https://gyazo.com/da262a849072b70cb53c18b16f567e41

OpenStudy (anonymous):

I have a huge test on this stuff tomorrow and for some reason I can't get _anything_ to work out

OpenStudy (anonymous):

The rectangular coordinates can be found by the formula: \[x=r*cos(a)\] \[y=r*sin(a)\] Where r is the length and is the angle

OpenStudy (anonymous):

so if I do x = 7 * cos(2pi/3)

OpenStudy (anonymous):

Yes, then you have the rectangular x coordinate

OpenStudy (anonymous):

7* -1/2 = -7/2

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

what about https://gyazo.com/9988ae7493b7d63ee2f5677115e79914

OpenStudy (anonymous):

?

OpenStudy (anonymous):

@SamsungFanBoy

OpenStudy (anonymous):

@Tommynaiter https://gyazo.com/da262a849072b70cb53c18b16f567e41

OpenStudy (anonymous):

@AlexandervonHumboldt2

OpenStudy (anonymous):

@imqwerty

OpenStudy (anonymous):

I feel like I think I know what I'm doing but the way I wanna do it feels ridiculously long

OpenStudy (anonymous):

I think I linked the wrong gyazo, this is the one that's giving me problems

OpenStudy (anonymous):

https://gyazo.com/14ef47a342447b44686220a3e5617aa0

OpenStudy (anonymous):

Got anything?

OpenStudy (anonymous):

@pooja195

OpenStudy (anonymous):

@thomaster

OpenStudy (anonymous):

https://gyazo.com/14ef47a342447b44686220a3e5617aa0

imqwerty (imqwerty):

okay we can write any complex number like Z=a+ib in this form-\[Z=r(\cos \theta +i \sin \theta)\]where\[r=\sqrt{a^2+b^2}\]

imqwerty (imqwerty):

ok did this help? lol

OpenStudy (anonymous):

To a point, I already knew that but I'm stuck on adding the angles to get the final form

OpenStudy (anonymous):

Like, I have 5pi/6 and pi/4 if I remember correctly but I can't get them to equal 23pi/12 or pi/12

OpenStudy (anonymous):

I think I did theta wrong

imqwerty (imqwerty):

oh ok ima tell that part :)

OpenStudy (anonymous):

https://gyazo.com/584527bec146ee0d4b47ea4b4609841c also for this I know that I do 2^3(cos(15*3)+isin(15*3)) but that gives me 8(cos45+isin45) 8(sqrt2/2 + (sqrt2/2)i) 4sqrt2 + 4sqrti did I do that right?

imqwerty (imqwerty):

ok \[\cos \theta=\frac{ a }{ \sqrt{a^2 +b^2} }\] \[\sin \theta=\frac{ b }{\sqrt{a^2+b^2 }}\] so here we shuld take the principle value of θ \[Z=r[\cos(2n \pi +\theta)+i \sin(2n \pi+ \theta)]\] where n is an integer try doing it now

OpenStudy (anonymous):

I think the answer is C

OpenStudy (anonymous):

But I did it differently, I converted each equation separately then divided r and subtracted the angles

OpenStudy (anonymous):

I mean I multiplied r1 with r2 and added the angles

OpenStudy (anonymous):

https://gyazo.com/62881a9809a919bc9db0e743d1a7b05a

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