Need help studying Polar/Cartesian forms and Trigonometric form
I have a huge test on this stuff tomorrow and for some reason I can't get _anything_ to work out
The rectangular coordinates can be found by the formula: \[x=r*cos(a)\] \[y=r*sin(a)\] Where r is the length and is the angle
so if I do x = 7 * cos(2pi/3)
Yes, then you have the rectangular x coordinate
7* -1/2 = -7/2
Yes
?
@SamsungFanBoy
@AlexandervonHumboldt2
@imqwerty
I feel like I think I know what I'm doing but the way I wanna do it feels ridiculously long
I think I linked the wrong gyazo, this is the one that's giving me problems
Got anything?
@pooja195
@thomaster
okay we can write any complex number like Z=a+ib in this form-\[Z=r(\cos \theta +i \sin \theta)\]where\[r=\sqrt{a^2+b^2}\]
ok did this help? lol
To a point, I already knew that but I'm stuck on adding the angles to get the final form
Like, I have 5pi/6 and pi/4 if I remember correctly but I can't get them to equal 23pi/12 or pi/12
I think I did theta wrong
oh ok ima tell that part :)
https://gyazo.com/584527bec146ee0d4b47ea4b4609841c also for this I know that I do 2^3(cos(15*3)+isin(15*3)) but that gives me 8(cos45+isin45) 8(sqrt2/2 + (sqrt2/2)i) 4sqrt2 + 4sqrti did I do that right?
ok \[\cos \theta=\frac{ a }{ \sqrt{a^2 +b^2} }\] \[\sin \theta=\frac{ b }{\sqrt{a^2+b^2 }}\] so here we shuld take the principle value of θ \[Z=r[\cos(2n \pi +\theta)+i \sin(2n \pi+ \theta)]\] where n is an integer try doing it now
I think the answer is C
But I did it differently, I converted each equation separately then divided r and subtracted the angles
I mean I multiplied r1 with r2 and added the angles
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