Question

The critical angle of refraction for calcite is 68.4 degrees when it forms a boundry with water. Using this information determine the speed of light in calcite.

Answer 1

The critical angle of refraction for calcite is 68.4° when it forms a boundary with water. Use this information to determine the speed of light in calcite


When a light ray travels from a more dense medium to a less dense medium, the angle between the light ray and the line perpendicular to the 2 surfaces increases. As the angle of incidence increases, the angle of refraction increases. At the critical angle of incidence, the angle of refraction = 90˚

This means the light ray is traveling along the line formed between the 2 surfaces.

n1 * sin θi = n2 * sin θ r
When θi = critical angle, θr = 90˚
Sin 90˚ = 1

n1 * sin θi = n2 * 1

sin θi = n2 / n1

sin 68.4˚ = n2 / n1
When determining the speed of light in a substance, n2 = 1, the index of refraction for a vacuum.

sin 68.4 = 1 / n1
n1 = 1/ sin 68.4

The speed of light in calcite = n1 * c = c * 1/ sin 68.4 = 3.23 * 10^8 m/s

Answer 2

i looked it up for you

Answer 3

:D

Answer 4

thank you so much!

Answer 5

NP #🌞🔑🌎