Question

MEDAL!!!

Answer 1

\[\large \frac{ -5 -\sqrt{3n} }{ -n - \sqrt{n^4} }\]

Answer 2

@Nnesha @mathstudent55 @Hero

Answer 3

what is the common factor at the top and bottom of the fraction ?

Answer 4

can you please tell me the answer? it's not a homework assignment. i just want to know.

Answer 5

@Nnesha

Answer 6

@jim_thompson5910

Answer 7

@Hero

Answer 8

what are the instructions @calculusxy ?

Answer 9

you need to simplify it

Answer 10

use the distributive property:\[\frac{ -5-\sqrt3*\sqrt n }{ -n-n^2}=\frac{ -5-\sqrt3*\sqrt n }{ -n*(1+n) }\]

Answer 11

I agree with what @AlexandervonHumboldt2 got, but tbh, I don't see that as much of a simplification

Answer 12

i just need the answer. it's not part of a test or homework.

Answer 13

please!

Answer 14

there's nothing that cancels

Answer 15

what do you mean?

Answer 16

well if we could factor out n from the numerator, for example, then the 'n' terms would divide and cancel out

Answer 17

you can take out the negative sign.

Answer 18

there is nothing to simplify

Answer 19

what i wrote is not a simplification, just some opration xD

Answer 20

@Nnesha has a good point, factor out -1 from the top and bottom, then divide

Answer 21

well what you can do is
\[\frac{ -5-\sqrt{3n} }{ -n-\sqrt{n^4} }=\frac{ -1*(5+\sqrt{3n}) }{ -1*(n+\sqrt{n^4}) }=\frac{ 5+\sqrt{3n} }{ n+\sqrt{n^4} }\]

Answer 22

maybe then you can just rationalize the denominator

Answer 23

can someone please give me their answer?

Answer 24

@Nnesha

Answer 25

do you have options ? (answer choices )

Answer 26

\[\frac{ 5n - 5n^2 + n \sqrt{3n}-n^2\sqrt{3n} }{ n^2 - n^4 }\]

Answer 27

No

Answer 28

i know i can simplify it more to:
\[\frac{ 5 - 5n + \sqrt{3n} - n \sqrt{3n} }{ n - n^3 }\]

Answer 29

ye that's it there is nothing to simplify anymore

Answer 30

so this answer is correct?

Answer 31

@Nnesha

Answer 32

i'm not 100% sure...

Answer 33

okay @jim_thompson5910

Answer 34

honestly, I'd just follow @AlexandervonHumboldt2 's steps

\[\Large \frac{ -5-\sqrt{3n} }{ -n-\sqrt{n^4} }\]
\[\Large \frac{ -1*(5+\sqrt{3n}) }{ -1*(n+\sqrt{n^4}) }\]
\[\Large \frac{ 5+\sqrt{3n} }{ n+\sqrt{n^4} }\]
\[\Large \frac{ 5+\sqrt{3n} }{ n+n^2 }\]

that's as simplified as it gets

Answer 35

^

Answer 36

so what's the answer?

Answer 37

depends on the statement simplify means something easier less complicated
if its says to `rationalize the denominator ` then you should multiply top and bottom by the conjugate
\[\frac{ -5-\sqrt{n} }{ -n+\sqrt{n^4} }\]
take out the negative one
\[\frac{- (5+\sqrt{3n} }{ -(n+\sqrt{n^4)}}\]
cancel out the negative sign
and then apply the exponent rule
\[\frac{\cancel{- }(5+\sqrt{3n}}{\cancel{ -}(n+n^{\frac{4}{2}})}\]
that's it divide 4/2
i'll go with this one if it says simplify