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Given the position function s(t), s(t) = t3 + 4t, where s is measured in meters and t is in seconds, find the velocity and acceleration of the particle at t = 2 seconds. a. 8 m/sec , 4 m/sec b.10 m/sec, 3 m/sec c.16 m/sec, 16 m/sec d. 16 m/sec, 12 m/sec
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Take the first derivative of \((t)=t^3+4t\) then substitute \(t=2\) to find the velocity.
Then take the second derivative and substitute \(t=2\) to find the acceleration.
ok, im doing it now
velocity=16 acce=12
Yes, you're correct! :)
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