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What is the percent yield if 106 g of sodium chlorite are isolated from the reaction of 202 g of chlorine dioxide with excess sodium hydroxide? I already have the balanced equation set up: 2 ClO2 + 2 NaOH > H2O + NaClO2 + NaClO3 What do I do from there? Please help
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Can you convert the initial 202 g of ClO2 to mole?
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