Three gases (8.00 g of methane, CH4, 18.0 g of ethane, C2H6, and an unknown amount of propane, C3H8) were added to the same 10.0-L container. At 23.0 ∘C, the total pressure in the container is 5.30 atm . Calculate the partial pressure of each gas in the container.

Question

raffle_snaffle · Answer

I solved this problem twice and seem to not obtain the correct answer....

raffle_snaffle · Answer

@abb0t

raffle_snaffle · Answer

Pmethane=121.26 atm
Pethane=1.45473atm
Ppropane=5.29999atm

raffle_snaffle · Answer

@kaylee_crps_strong

raffle_snaffle · Answer

@Photon336

anonymous · Answer

I haven't learned this I'm sorry! :/

abb0t · Answer

So, find the moles of each organic compound first.
then, find the total moles of propane (unknown)-
$\sf \color{red}{HINT}$ use PV = nRT

You already have P, V, and T, solve for $n$.
Since they are all in the same container, you can simply subtract the total amount of moles from the amount of propane in the tank to get the moles of propane.

Then, you can find the partial pressure for each individually.

abb0t · Answer

The pressure you got for methane seems highly unusual, especially since it's above the critical pressure for methane, in which case you wouldn't have a gas anymore...

raffle_snaffle · Answer

Thanks, got it.