Question

Two fair dices are thrown. Given that the sum of the dice is less than or equal to 4, find the probability that only one dice shows 2.

Answer 1

Total number of outcomes are 36 in number.

Answer 2

Sample Space =
{(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}

Answer 3

Remember \[Probability = \frac{ \text{number of favourable outcomes} }{\text {number of possible outcomes} } \]

Answer 4

for outcome on the dice to be sum of less than or equal to 4 = 6

Answer 5

for 2 coming one one of the dice, will be 2.

Answer 6

Since we have two fair dices (6 each) that means the maximum combination is 36 right? So how many rolls can you get with 2, also note 1 die must be 2.

Answer 7

You can find the sum after