Geometry
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OpenStudy (erty):
How would I slove ((x^2-9^2) +3^2) + x^2= ?
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OpenStudy (erty):
^2 means squared
OpenStudy (erty):
Please help!!!
OpenStudy (astrophysics):
What do you mean by solve?
OpenStudy (astrophysics):
\[(x^2-9^2)+3^2+x^2\]
OpenStudy (astrophysics):
What exactly do you want to do with this
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OpenStudy (erty):
I got help from a tutor and he said for me to finish the problem I need to solve that.
OpenStudy (astrophysics):
You mean simplify
OpenStudy (astrophysics):
Just drop the brackets and collect like terms
OpenStudy (erty):
oh and i forgot it equals to 12^2
OpenStudy (astrophysics):
\[(x^2-9^2)+3^2+x^2 = 12^2\]
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OpenStudy (erty):
yes
OpenStudy (astrophysics):
Ok first thing, lets drop the brackets and simplify the left side
OpenStudy (erty):
ok
OpenStudy (astrophysics):
So go ahead and try that, and remember 9^2 = 81, and 3^2 = 9
OpenStudy (astrophysics):
12^2 = 144
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OpenStudy (astrophysics):
The exponents tell you how many times it's being multiplied by itself
OpenStudy (astrophysics):
9^2 = 9 * 9 = 81
OpenStudy (erty):
I got 6
OpenStudy (astrophysics):
What do you mean
OpenStudy (erty):
I squared them and then got -72
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OpenStudy (erty):
then i squared 12
OpenStudy (astrophysics):
just show the math here step by step
OpenStudy (astrophysics):
Because you should get two solutions
OpenStudy (erty):
wait I found a mistake
OpenStudy (erty):
I don't know. I can't get it. The answers I chose from are: A 10.5 B 10 C 6 root 3 D 20
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OpenStudy (erty):
Is your answer one of those?
OpenStudy (astrophysics):
\[x^2-81+9+x^2=144\] dropping the brackets and squaring, so simplify the left side a bit what do we get
OpenStudy (astrophysics):
Take it step by step
OpenStudy (erty):
2x^2 -72=144
OpenStudy (astrophysics):
Yes, good now what's next?
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OpenStudy (erty):
add 72
OpenStudy (astrophysics):
Right what do you get
OpenStudy (erty):
216
OpenStudy (astrophysics):
Good so we have \[2x^2 = 216\]
OpenStudy (astrophysics):
next?
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OpenStudy (erty):
yes
OpenStudy (erty):
divide 2
OpenStudy (astrophysics):
good then we get?
OpenStudy (erty):
108
OpenStudy (erty):
then we square root it
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OpenStudy (astrophysics):
Right! When we square we actually get a positive and negative solution but it seems they just want a positive answer so lets say \[x=\sqrt{108}\]
OpenStudy (erty):
but there is no answer like that in my multiple choice
OpenStudy (astrophysics):
Now we need to simplify 108 in the radical
OpenStudy (erty):
the only radical there is, is 6 root 3
OpenStudy (astrophysics):
\[\sqrt{108} = \sqrt{36 \times 3} = 6\sqrt{3}\]
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OpenStudy (erty):
ok. Thanks!
OpenStudy (erty):
Thank you! I got it correct!
OpenStudy (astrophysics):
Yw