Question

Determine the equation of the tangent to the curve y=2-xe^x at the point where x=0

Answer 1

Find the derivative using product rule

Answer 2

yes

Answer 3

Then plug in x=0 into your derivative

Answer 4

That will give you your (x,y) then you can set it up into y = mx+b form, where b is the y - intercept which you get by plugging in x = 0 into your derivative

Answer 5

@MTALHAHASSAN2 understood ?

Answer 6

yes i do understand it but need help with finding derivative

Answer 7

why not

Answer 8

\[\large \bf y=2-xe^x\]

Answer 9

\[\large \bf y^/=-(xe^x+e^x) ~~~~[\color{red}{Using~Product~rule}]\]

Answer 10

hope you understand !

Answer 11

@MTALHAHASSAN2

Answer 12

@Astrophysics can you help me solving this question

Answer 13

Hey sure, I think you just need help on understanding what product rule is

Answer 14

The easiest way to remember it is, \[(f g) = f'g+g'f\] where f and g are functions so when they are multiplied you can use that rule, which is the product rule

Answer 15

oh now i remember but know do i have to plug 0 instead of x

Answer 16

Yes once you have the derivative