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Mathematics 7 Online
OpenStudy (anonymous):

whoever gives me the first answer to the question gets a medal!

OpenStudy (anonymous):

Which statement best explains whether the table represents a linear or nonlinear function? Input (x) Output (y) 0 1 1 2 2 4 3 16 It is a linear function because there is a constant rate of change in both the input and output values. It is a nonlinear function because there is a constant rate of change is both the input and output values. It is a linear function because the output values are increasing at different rates. It is a nonlinear function because the output values are increasing at different rates.

OpenStudy (astrophysics):

Have you tried graphing it?

OpenStudy (astrophysics):

I think if you graph it, you will have a better picture of what's going on

OpenStudy (anonymous):

OpenStudy (amistre64):

the options suggest finding the slope (rate of change) between points

OpenStudy (amistre64):

also, a line is an arithmatic progression of points

OpenStudy (anonymous):

cool!

OpenStudy (amistre64):

2 options are simply contradictions of a line function. does a line have a constant rate of change? or does it differ?

OpenStudy (anonymous):

i think its straight.

OpenStudy (anonymous):

It is a linear function because there is a constant rate of change in both the input and output values.

OpenStudy (amistre64):

x changes by 1 each time does y have a constant change each time? and what is it?

OpenStudy (astrophysics):

If you want \[m = \frac{ y_{2}-y _{1} }{ x _{2}-x _{1} }\] here is the slope formula

OpenStudy (anonymous):

y increases by 2 except for the last one, it is exaggerated

OpenStudy (amistre64):

1+d=2 2+d =4 is this possible if d is the same each time?

OpenStudy (anonymous):

i guess not...

OpenStudy (amistre64):

as x changes by 1each time, y does not have a constant rate of change

OpenStudy (anonymous):

ok so its D. It is a nonlinear function because the output values are increasing at different rates.

OpenStudy (amistre64):

correct :)

OpenStudy (anonymous):

Thank you!

OpenStudy (amistre64):

youre welcome

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