Question

can someone help me with the steps of graphing these two inequalities? They're in the comment section! :) Thanks ~

Answer 1

how did you get that ? what steps did you use?

Answer 2

honestly: i used a graphing tool
but when i have to physically do these (like pen to paper) i draw them as
x + y = 4

and
2x - y = 2

once i have the lines drawn for those equations, i switch it back to an inequality and shade whichever side is correct, depending on the sign (greater than or less than)

...does that make sense?
are are u ok with graphing linear equations?
ie y = mx + c type equations

Answer 3

yeah i get that part but how did you graph them if they weren't already in y=mx+b form?

Answer 4

like, break it down for me :3

Answer 5

well... look at ur first equation
x + y = 4
y = -x + 4
so ur gradient is -1
and ur y intercept is 4

so all u need is 2 points to graph any straight line... right?
point 1: y intercept (0, 4)

now find point 2
easiest way, find x intercept... so y = 0
y = -x + 4
0 = -x + 4
x = 4

point 2 is (4,0)

draw those 2 points on ur graph, get a ruler... line drawn... done

now, ur inequality is
x + y > 4
so everything greater than 4
so every number to the right of your line is greater than 4

so shade everything to the right of your line.... with me so far dude?

Answer 6

yeup im here !

Answer 7

cool... so u get the gist of how to do these then?

Answer 8

yeah i getchu man! so wait for the second one would it be
2x-y=2 ----> -y=-2x+2? (the y intercept being 2 and the first point would be -2,1?)

Answer 9

yeaaaah.... mostly right, ummm:
y intercept would be * -2 ... not 2 tho
and 1st point would be (0, -2)
2nd point is x intercept (if u want) and it would be (1,0)... yeah?

Answer 10

haha okidoke thanks man! :D

Answer 11

np man ;)