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OpenStudy (bluebeta):
Help attaching picture
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OpenStudy (bluebeta):
.
OpenStudy (anonymous):
Okay. So in an equation the points (h, k) is the center.
OpenStudy (anonymous):
This is the template for all the equations...
\[(x – h)^2 + (y – k)^2 = r^2\]
OpenStudy (bluebeta):
okay im following
OpenStudy (anonymous):
So for number 2 we can see that the center is:
\[(4, -7)\]
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OpenStudy (anonymous):
Do you see what I did?
OpenStudy (bluebeta):
Sorta. But how do we get #1?
OpenStudy (anonymous):
Well I am going to help with that last, because the rest are faster.
OpenStudy (anonymous):
Now part 2 of number 2..
OpenStudy (anonymous):
What is the radius of the equation...
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OpenStudy (anonymous):
So \[r^2\] is the radius squared.
OpenStudy (anonymous):
So in this \[r^2\] is 4 so we have to square root 4 and we would get 2!
So the radius is 2!
OpenStudy (anonymous):
Do you see that? @bluebeta
OpenStudy (anonymous):
Now just do the same to the rest.. now lets do number 1.
OpenStudy (bluebeta):
Yes, I see it.
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OpenStudy (anonymous):
It would be:
\[(x - 12)^2 + (y + 16)^2 = 16\]
OpenStudy (anonymous):
Hope this helped! Have a great day!
Also a medal would be much appreciated! Just click best response next to my answer. Thank You!
@bluebeta
OpenStudy (bluebeta):
@Tom_Boy_Rebel You're awesome!! You helped me understand a bit better! Thanks!
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