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Chemistry 19 Online
OpenStudy (anonymous):

What is the Na+ concentration in each of the following solution: .485M sodium bicarbonate:

OpenStudy (anonymous):

@jebonna

OpenStudy (anonymous):

I have to go right now. I'll be back later. If you want you can just explain and work out the problem if you want to so I can follow along with the steps and see what you did. Sorry!!!

OpenStudy (jebonna):

Na2SO4 -----> 2Na^+ + SO4^2- M stands for molarity (moles of solute)/(Liters of solution) so 1 litre contains 0.485M of Na2SO4. If sodium bicarbonate is 0.485M (1 mol), then the concentration of Na will be the concentration of sodium bicarbonate times 2 (as Na has a 2 in front of it) 0.485 x 2 = 0.97M So the concentration of Na+ = 0.97M Since there is no volume given, we have to work theoretically and assume it is 1L. To work these out just break the compound up into an equation and balance it and then use the stoichiometry to work out the concentration I think that's right but maybe get a second opinion :)

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