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Mathematics 14 Online
OpenStudy (leahhhmorgannn):

The figure below shows triangle NRM with r^2 = m^2 + n^2: http://prntscr.com/94cadg Ben constructed a right triangle EFD with legs m and n, as shown below: http://prntscr.com/94cai7 He made the following table to prove that triangle NRM is a right triangle: http://prntscr.com/94can9 Which reason best fits statement 4? SAS postulate AAS postulate Square Root Property of Equality Triangle Proportionality Theorem I don't think it's C or D, but I'm also not too sure.

OpenStudy (leahhhmorgannn):

@superdavesuper

OpenStudy (superdavesuper):

explain why u dont think its C or D @leahhhmorgannn

OpenStudy (leahhhmorgannn):

Well, according to the resource sheet my school gave me: http://prntscr.com/94cbsq http://prntscr.com/94cbw5 And I just don't think those fit with the question But I'm also not good with this stuff so

OpenStudy (superdavesuper):

compare the first screen shot u just posted n what was done between statement 3 and 4.....

OpenStudy (leahhhmorgannn):

I can't tell what happened from statement 3 to statement 4... As I've stated before, I'm not good at these, whatsoever. @superdavesuper

OpenStudy (superdavesuper):

hmmm u dont know what math operator will change \[t^{2}\] to t ? perhaps u should read ur study material again n try to understand it better.

OpenStudy (leahhhmorgannn):

First of all, there was no study material. Just a list of postulates and theorems, which makes no sense to me. Second, no, I don't know what happens from one step to another. I'm not even sure how to read that.

OpenStudy (superdavesuper):

hmmm....check this plz https://www.mathsisfun.com/square-root.html

OpenStudy (leahhhmorgannn):

I get square roots, that was like third grade. So what, that t squared looks like it's getting unsquared? That's not helping me understand this at all.

OpenStudy (leahhhmorgannn):

I can honestly say that I don't know anything about this question.

OpenStudy (superdavesuper):

Great - u know square root :) u got me worried 4 a moment there! lol so isn't it a square root function in going from Step 3 to 4?

OpenStudy (leahhhmorgannn):

See, the wording of the definition they gave me for the square root property of equality just confuses me But yes, it is a function to do with square roots. Now I have a question - can you un-square something? Because that's what it looks like they're doing from Steps 3 to 4.

OpenStudy (superdavesuper):

err...."un-square" = square root...

OpenStudy (leahhhmorgannn):

Again, I don't know.

OpenStudy (superdavesuper):

@jim_thompson5910 help plz?

OpenStudy (superdavesuper):

which part u dont know @leahhhmorgannn ? i just stated "un-square" is the same as square root.

OpenStudy (leahhhmorgannn):

I just don't get any of it. It's just all confusing to me. You have to understand that you know math very well, but it's all like a foreign language to me.

OpenStudy (superdavesuper):

@leahhhmorgannn sorry im not very good at explaining; thats why i tagged @jim_thompson5910 who is much better than im... i can tell u the ans is C but im having trouble in explaining why that is the right ans to u. sorry! :(

OpenStudy (leahhhmorgannn):

@jim_thompson5910 do you wanna try? I know you've helped me a lot before.

OpenStudy (leahhhmorgannn):

thanks for trying, dave.

OpenStudy (superdavesuper):

welcome n good luck! :)

jimthompson5910 (jim_thompson5910):

Sorry I'm reading and thinking about how to approach this

jimthompson5910 (jim_thompson5910):

@leahhhmorgannn do you agree that \[\Large \sqrt{f^2} = f\] ?

OpenStudy (leahhhmorgannn):

I was just about to say that after I thought a bit about it. Yes, I do agree.

OpenStudy (leahhhmorgannn):

And that's the same basic thing the definition of the theorem says, right?

jimthompson5910 (jim_thompson5910):

yes, just replace 'a' with 'f'

jimthompson5910 (jim_thompson5910):

similarly, \[\Large \sqrt{r^2} = r\]

OpenStudy (leahhhmorgannn):

And doing the same thing with 'r' would make sense too

OpenStudy (leahhhmorgannn):

yeah, just like that

OpenStudy (leahhhmorgannn):

Okay, so once I stopped stressing myself out by doubting myself, that was easy to understand and relate.

jimthompson5910 (jim_thompson5910):

The square root of equality theorem basically says that if \[\Large a = b\] then \[\Large \sqrt{a} = \sqrt{b}\] You apply the square root to both sides to balance tings out

OpenStudy (leahhhmorgannn):

That makes sense.

jimthompson5910 (jim_thompson5910):

which is why we get \[\Large f^2 = r^2\] \[\Large \sqrt{f^2} = \sqrt{r^2}\] \[\Large f = r\]

OpenStudy (leahhhmorgannn):

Because the equations are always balanced and f will equal r as long as whatever change you're making is applied to each side, right?

jimthompson5910 (jim_thompson5910):

correct, as long as it happens to both sides

OpenStudy (leahhhmorgannn):

so is that all it takes to figure out the answer or are there more things to consider?

jimthompson5910 (jim_thompson5910):

nope, the only thing that goes in the blank is "square root property of equality". You can do those expanded steps, or you can take a shortcut like they did in this 2 column proof table

OpenStudy (superdavesuper):

able to calmly explain something, thats why u ARE the professor @jim_thompson5910 :)

OpenStudy (leahhhmorgannn):

Thank you so much! You're really just great at explaining things, @jim_thompson5910

jimthompson5910 (jim_thompson5910):

thank you for the compliments, and you're welcome

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