The figure below shows triangle NRM with r^2 = m^2 + n^2: http://prntscr.com/94cadg Ben constructed a right triangle EFD with legs m and n, as shown below: http://prntscr.com/94cai7 He made the following table to prove that triangle NRM is a right triangle: http://prntscr.com/94can9 Which reason best fits statement 4? SAS postulate AAS postulate Square Root Property of Equality Triangle Proportionality Theorem I don't think it's C or D, but I'm also not too sure.
@superdavesuper
explain why u dont think its C or D @leahhhmorgannn
Well, according to the resource sheet my school gave me: http://prntscr.com/94cbsq http://prntscr.com/94cbw5 And I just don't think those fit with the question But I'm also not good with this stuff so
compare the first screen shot u just posted n what was done between statement 3 and 4.....
I can't tell what happened from statement 3 to statement 4... As I've stated before, I'm not good at these, whatsoever. @superdavesuper
hmmm u dont know what math operator will change \[t^{2}\] to t ? perhaps u should read ur study material again n try to understand it better.
First of all, there was no study material. Just a list of postulates and theorems, which makes no sense to me. Second, no, I don't know what happens from one step to another. I'm not even sure how to read that.
I get square roots, that was like third grade. So what, that t squared looks like it's getting unsquared? That's not helping me understand this at all.
I can honestly say that I don't know anything about this question.
Great - u know square root :) u got me worried 4 a moment there! lol so isn't it a square root function in going from Step 3 to 4?
See, the wording of the definition they gave me for the square root property of equality just confuses me But yes, it is a function to do with square roots. Now I have a question - can you un-square something? Because that's what it looks like they're doing from Steps 3 to 4.
err...."un-square" = square root...
Again, I don't know.
@jim_thompson5910 help plz?
which part u dont know @leahhhmorgannn ? i just stated "un-square" is the same as square root.
I just don't get any of it. It's just all confusing to me. You have to understand that you know math very well, but it's all like a foreign language to me.
@leahhhmorgannn sorry im not very good at explaining; thats why i tagged @jim_thompson5910 who is much better than im... i can tell u the ans is C but im having trouble in explaining why that is the right ans to u. sorry! :(
@jim_thompson5910 do you wanna try? I know you've helped me a lot before.
thanks for trying, dave.
welcome n good luck! :)
Sorry I'm reading and thinking about how to approach this
@leahhhmorgannn do you agree that \[\Large \sqrt{f^2} = f\] ?
I was just about to say that after I thought a bit about it. Yes, I do agree.
And that's the same basic thing the definition of the theorem says, right?
yes, just replace 'a' with 'f'
similarly, \[\Large \sqrt{r^2} = r\]
And doing the same thing with 'r' would make sense too
yeah, just like that
Okay, so once I stopped stressing myself out by doubting myself, that was easy to understand and relate.
The square root of equality theorem basically says that if \[\Large a = b\] then \[\Large \sqrt{a} = \sqrt{b}\] You apply the square root to both sides to balance tings out
That makes sense.
which is why we get \[\Large f^2 = r^2\] \[\Large \sqrt{f^2} = \sqrt{r^2}\] \[\Large f = r\]
Because the equations are always balanced and f will equal r as long as whatever change you're making is applied to each side, right?
correct, as long as it happens to both sides
so is that all it takes to figure out the answer or are there more things to consider?
nope, the only thing that goes in the blank is "square root property of equality". You can do those expanded steps, or you can take a shortcut like they did in this 2 column proof table
able to calmly explain something, thats why u ARE the professor @jim_thompson5910 :)
Thank you so much! You're really just great at explaining things, @jim_thompson5910
thank you for the compliments, and you're welcome
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