I am willing to work. I want to understand and contribute to the answer. Is triangle ABC with vertices A(-1, 4), B(3,1), and C(0,-3) a right triangle? Explain your answer using the slopes of the segments that form the sides of the triangle. I will include the visual document once the thread is open.
Did you find the slopes?
I'm currently working on that right now, we can go through each slope together, or you could wait a few minutes for me to finish up, sorry.
You have to find all the slopes of each segment. If two of those slopes are perpendicular to each other, then you know itʻs a right triangle
Perpendicular means it creates a 90 degree angle. You will know this if you find a slope that is an opposite reciprocal to another slope
For example 3 --> -1/3 2 ---> -1/2
|dw:1447914844159:dw|
Ok, I see what your saying. If you don't mind, could we possible first go over the finding the slope for each vertices together?
Do you know the formula that you would use?
There is a quick way of doing this, and then there is the harder way
I know in Algebra we use the m = Rise/Run, but I since this is Geometry wouldn't we be finding the medians of a triangle (vertices)?
For example, (xM, yM)...
The formula that you would use is \[m = y _{2} - y _{1} \over x _{2} - x _{1}\]
You would just throw the vertices in, and find the slope of each length, one by one
That is the harder and longer way, yet it may be more clear to you. Would you want me to show you the easier way?
The easier way is better for tests, and quickly moving through problems
I would like to observe the easier way, but could I also see the 'original' way as well later on?
Sure
Well, which way would you like to cover first? I would like to aid you in anyway possible.
Showing the easier way first
Ok so what you want to do is observe the triangle, and know what youʻre looking for. Youʻre looking for a 90 degree angle to prove that this is a right triangle. We know that it is a right triangle if itʻs the slopes of two segments, that are connected to the angle, are perpendicular to each other
For this, you can take advantage of the fact that this triangle is on a grid. You can count the units and determine the slopes easily without a formula. |dw:1447915570510:dw|
So I counted the units, and this is what I got
Let me tell you how I got that
So counting the units isnʻt too hard, but, you can count 7 units easily, how do you know it is negative? This is simple |dw:1447915761140:dw| Notice how that line looks like it is angling down, like itʻs falling. Whenever you see a line like this, you know it has a negative slope. The slope of -7 is very steep, but notice how it follows that same motion, of going from the top left to the bottom right
Positive slopes, like 4/3, look like they are rising up. Btw, this is why itʻs called slope...like the slope of a mountain. They can be steep, or rise slowly. |dw:1447915872206:dw| Positive slope Itʻs goes from the bottom left, to the top right Rising up like a mountain Positive slopes will look similar, but remember, like the -7 slopes, they can be steep like this |dw:1447915917542:dw| If ever unsure, use the slope formula, especially if your grade is counting on it
Any questions so far?
No, I believe I got. Just to make sure, this was the easy way right?
Yeah, you just have to make these observations, notice them, and itʻs just cake
Iʻm just explaining why these observations work, so you understand it. So you wonʻt make any mistakes
I've actually done it that way before, thank you for explaining it! Could we possible go over the formal way of doing it, if you have time?
Yeah, no problem
So the more formal way is using the slope formula Remember it! \[m = y _{2} - y _{1} \over x _{2} - x _{1} \]
The line doesnʻt go under the m, donʻt write it like that, idk why itʻs doing that |dw:1447916219715:dw| Like that
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