Question

3 step synthesis of cylcopentane to 3-bromocylcopentene?

Answer 1

First, label your substrate and product.
How wold a cyclopentane look like (for the substrate), and how would 3-bromocyclopentene look like for the product?

Answer 2

What would be on the first box and the last box? They already gave you the names for it.

Answer 3

@xlovely_Lizardx you there?

Answer 4

cyclopentane is just a 5 carbon ring and 3-bromocylopentene is a 5 carbon ring with a double bond and a br sub

Answer 5

@Zale101 you still there?

Answer 6

@Jaynator495 are you able to help with this?

Answer 7

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Answer 8

We see that the product has both an alkene and an alkyl halide bromine. I can't think of a reagent that can create both the alkene and alkyl halide. That's why there's 3 steps to this mechanism.

Answer 9

We also have a cycloalkane, alkane not alkene, as a substrate without any leaving groups attached to it. Let us first examine what type of reaction is it.

Is it an substitution reaction, elimination reaction, addition reaction, or a radical reaction?

Substitution reaction--> Also called single replacement reaction because its functional group is replaced by another functional group. The substrate has to have a functional group which can be replaced by the nucleophile. There are two types of substitution reactions, SN2 and SN1. Does out substrate that we have, Cyclopentane consists of a functional group? No

Elimination reaction-->"An elimination reaction is a type of organic reaction in which two substituents are removed from a molecule in either a one or two-step mechanism.The one-step mechanism is known as the E2 reaction, and the two-step mechanism is known as the E1 reaction" https://en.wikipedia.org/wiki/Elimination_reaction I like this definition from wikipedia. Basically, an elimination reaction occurs when a base grabs a proton that is adjacent to leaving group, which the electron on the hydrogen will create an alkene or an alkyne. You can read more on this in http://chemwiki.ucdavis.edu/Organic_Chemistry/Reactions/Elimination_Reactions
However, we need an LG on our substrate, do we have an LG in cyclopentane? No

Addition reactions--> is the reverse of elimination reaction. Instead of taking a substrate with function groups to change it to an alkene or an alkyne, you take an alkene or an alkyne and add functional groups by. You start with an alkene or an alkyne. In this case, but we have an alkane instead.

Answer 10

We also have a cycloalkane, alkane not alkene, as a substrate without any leaving groups attached to it. Let us first examine what type of reaction is it. Is it an substitution reaction, elimination reaction, addition reaction, or a radical reaction?

Substitution reaction--> Also called single replacement reaction because its functional group is replaced by another functional group. The substrate has to have a functional group which can be replaced by the nucleophile. There are two types of substitution reactions, SN2 and SN1. Does out substrate that we have, Cyclopentane consists of a functional group? No.

Elimination reaction-->"An elimination reaction is a type of organic reaction in which two substituents are removed from a molecule in either a one or two-step mechanism.The one-step mechanism is known as the E2 reaction, and the two-step mechanism is known as the E1 reaction"
https://en.wikipedia.org/wiki/Elimination_reaction
I like this definition from wikipedia. Basically, an elimination reaction occurs when a base grabs a proton that is adjacent to leaving group, which the electron on the hydrogen will create an alkene or an alkyne. You can read more on this in
http://chemwiki.ucdavis.edu/Organic_Chemistry/Reactions/Elimination_Reactions
However, we need an LG on our substrate, do we have an LG in cyclopentane? No.

Addition reactions--> is the reverse of elimination reaction. Instead of taking a substrate with function groups to change it to an alkene or an alkyne, you take an alkene or an alkyne and add functional groups by. You start with an alkene or an alkyne. In this case, we have an alkane instead.

Answer 11

In this case, we are left with radical reactions. It is the only reaction from the reactions i listed above that treats a normal alkane to give a product. The product it will produce is an alkyl halide.