Question

please helllp! how to find a quadratic function given the maximum value of 6 when x=-2 and one zero is 1?

Answer 1

you can start by writing it in vertex form as \[f(x)=a(x+2)^2+6\]

Answer 2

then solve for \(a\) by setting \(f(1)=0\)

Answer 3

Why do I set it to zero?

Answer 4

Or how do I know to set it to zero?

Answer 5

`one zero is 1` means that f(1) = 0

`one zero is 1` is another way of saying `x = 1 is a root of f(x)` or `x = 1 is an x intercept of f(x)`

Answer 6

\[f(1)=0\\
f(1)=a(1+2)^2+6=0\]

Answer 7

i.e. \[9a+6=0\] solve that one

Answer 8

-2/3

Answer 9

whoaa wait hold the phone
is there a typo in this question?

Answer 10

" find a quadratic function given the minimum value of 6 when x=-2 and one zero is 1?"

Answer 11

maximum...

Answer 12

or does it say maybe "MAXIMUM"?

Answer 13

whew

Answer 14

and yes \[a=-\frac{2}{3}\]