did i do this right ?

Question

anonymous · Answer

attachment

mathmale · Answer

It's asking a lot of others to want them to review all of your work and tell you if you're correct or not.  In the first problem, you are to simplify and solve for x:  2Sqrt(x)=Sqrt(12).  You came up with x=6.  To check this answer, substitute x=6 into the original equation and determine whether that equation is now true (or false).  It's so much better to be able to check your own work.

anonymous · Answer

the first one is wrong

anonymous · Answer

the second one is an expression, not an equation 
there is nothing to "solve" you can write it in simplest radical form. your answer will have a $b$ in it

anonymous · Answer

the third and fourth are also wrong 
dang!

anonymous · Answer

which one would you like to do first?

anonymous · Answer

can we start fromthe beginning @satellite73

thesmartone · Answer

sure! :)

thesmartone · Answer

$\sf\Large( 2\sqrt{x} )^2 = 2^2 \sqrt{x}^2 = ?$

thesmartone · Answer

Also, @mathmale 

When an asker provides his work and asks us to make sure if it is correct, it is easier on us, the helpers. We can tell what he knows, and we can guide him better.

anonymous · Answer

does x = 1.7 @TheSmartOne ?

thesmartone · Answer

we cannot get x = something just yet

I need you to simplify what I wrote above...

For example, what is 2^2 = ?

anonymous · Answer

4 @TheSmartOne

thesmartone · Answer

correct, and so what is $\sf\Large \sqrt{x}^2 = ?$

anonymous · Answer

12? @TheSmartOne

thesmartone · Answer

how would you get 12? :)

anonymous · Answer

because the equation equals the suare root of 12

anonymous · Answer

@TheSmartOne

thesmartone · Answer

we're not considering the other side of the equation just yet. :)

thesmartone · Answer

$\sf\Large \sqrt{x}^2 =(x^{\frac{1}{2}})^2 = ?$

anonymous · Answer

is this right @TheSmartOne

wmj259 · Answer

in order to solve for x, you must simplify and get rid of the square root which the x is "trapped inside". In order to rescue the "x" princess, you must take both sides of the equation and square both sides. You seem to be having trouble squaring the quantity $$(2\sqrt{x})^{2}$$. Because the WHOLE quantity is being squared you must individually square each term inside the quantity. There fore what is [(2\sqrt{x})^{2}\]?