Question

8th grade math help pls

Answer 1

hi

Answer 2

5x+y=5

Answer 3

?

Answer 4

@imqwerty

Answer 5

u have to substitute one of them for x or y

Answer 6

i know that but i don't have time to go through the whole number grid

Answer 7

so the second one is good bc there is no number

Answer 8

what are you taking about :(

Answer 9

DX

Answer 10

it is xd

Answer 11

i don't think you guys understand the question i asked

Answer 12

x=y+3 so u plug it in the other one
4(y+3)+y=2
4y+12=2
4y=-10
y=-10/4
y=-5/2

Answer 13

u have these 2 equations-\[4x+y=2 \]\[x-y=3\]
add them together\[4x+y+x-y=2+3\]\[5x=5\]\[\frac{ 5x }{5 }=\frac{ 5 }{ 5 }\]\[x=1\]now we have x=1 put this value of x in any of the original equations to get y

like i choose to put it in the second equation so\[x-y=3\]\[1-y=3\]\[y=-2\]

Answer 14

no

Answer 15

1,-2

Answer 16

thx imqwerty

Answer 17

so this is =\[\frac{ 5 }{ 2 }\]