Question

Find the distance between (3, 8) and (7, -11). Round to the nearest hundredth. quick medal

Answer 1

Use the distance formula :)
\[\huge d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\]

Answer 2

\[\huge d=\sqrt{(7-3)^2+(-11-8)^2}\]
\[\huge d=\sqrt{(4)^2+(-19)^2}\]
Ill let u finish it off :)

Answer 3

19.416 so rounding to the nearest hundredth would be? not good at rounding

Answer 4

we
4^2=16
-19^2=361
\[\huge d=\sqrt{(16+361}\]
\[\huge d=\sqrt{377}\]
I assume you can leave it as that and if you wanted to round it you can round to the nearest hundredth which would be 19.42

Answer 5

thanks

Answer 6

np