Find the value of y so that the line passing through (9, 0) and (3, y) has a slope of QUICK MEDAL
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OpenStudy (alexandervonhumboldt2):
\[\frac{ y_1-y_2 }{ x_1-x_2 }=slope\]
OpenStudy (alexandervonhumboldt2):
just substitute the given values and then solve:
OpenStudy (alexandervonhumboldt2):
what is the value of slope? i dont see it.
OpenStudy (alexandervonhumboldt2):
\[\frac{ 0-y }{ 9-3 }=slope\]
slope if given, so just solve
OpenStudy (anonymous):
\[\frac{ 0-y }{ 9-3 } = \frac{ -y }{ 6 }\]
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OpenStudy (alexandervonhumboldt2):
yes
OpenStudy (alexandervonhumboldt2):
what is the value of slope? you haven't written it:
your questions says: Find the value of y so that the line passing through (9, 0) and (3, y) has a slope of QUICK MEDAL
but what is the vlue of slope?
OpenStudy (anonymous):
1/2
OpenStudy (alexandervonhumboldt2):
ok thus we have
\[\frac{ -y }{ 6 }=\frac{ 1 }{ 2 }\]
how solve this equation
OpenStudy (anonymous):
i meant -1/2
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OpenStudy (alexandervonhumboldt2):
ok
OpenStudy (alexandervonhumboldt2):
\[\frac{ -y }{ 6 }=-\frac{ 1 }{ 2 }\]
OpenStudy (alexandervonhumboldt2):
solve this
OpenStudy (anonymous):
i dont know how
OpenStudy (alexandervonhumboldt2):
you have to multply both sides by 6:
\[\frac{ -y }{ 6 }*6=-\frac{ 1 }{ 2 }*6\]
\[-y=-3\]
thus y=3
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