Question

I need help. https://41.media.tumblr.com/1c5b37c0843f7e2bead1d18ed59e2a09/tumblr_ny53t48ypd1u97y0go1_1280.png

Answer 1

Step 1) Identify the corner points of the feasible region

Step 2) plug each point, one at a time, into the objective function

Step 3) The smallest output in step 2 is the min value of z

Answer 2

(0,8)
(0,6)
(8,8)
(4,4)

Answer 3

y=6x-1/2z

Answer 4

I think you mean `z = 3x - (1/2)y` right?

Answer 5

i tried rearranging it

Answer 6

im seeing it will be easier to keep it the same tho

Answer 7

I'm not sure what you mean. But let's say we plugged in the point (0,8)

so x = 0 and y = 8

z = 3x - (1/2)y
z = 3*0 - (1/2)*8
z = 0 - 4
z = -4

if the input is (x,y) = (0,8) then the output is z = -4

Do the same for the other corner points you listed. Tell me what outputs you get (and the corresponding inputs)

Answer 8

yeah i just was writing it differently but i got -4 too yay and i understand so thank you!!!

Answer 9

you're welcome