Question

A bond between calcium (Ca) and bromine (Br) would be considered __________.
nonpolar covalent
polar covalent
ionic
metallic

Answer 1

Metallic bonding is bonding between a localized sea of electrons.
Ionic bonding is bonding where there is a great difference in Electronegativity between the two bonded atoms. Electrons are transferred to one atom in this bond.
Polar covalent bonding there is less of an electronegativity difference than that of ionic bonding. Electrons are shared between the atoms in this bond.
NonPolar covalent there is no difference in electronegativity between the bonded atoms. Electrons are shared between atoms.

Answer 2

@sweetburger can you explain localized sea of electrons? In that bonding network

Answer 3

Well i guess it isn't necessarily considered bonding in metals its more the electrons in a group of metals become delocalized and form a large sea of electrons surrounding the nucleus.

Answer 4

it's Ionic because other choice are wrong.
It's not covalent because its made up by one metal and a non metal. So first two choices are wrong and the last one it also wrong because it's not two metals. Ionic is correct because a metal and nonmetal bonds together.

Answer 5

Because this is a bond between a metal element (Ca) and a nonmetal element (Br), it is considered an ionic bond. Ca, the cation in this bond, will lose 2 of its valence shell electrons. 2 Br atoms are required to complete the bond. Each Br atom will gain one electron.
\[Ca+2Br \rightarrow CaBr _{2}\]
The charges of the atoms within the bonded compound are as follows:
Calcium is oxidized (because it loses electrons)
\[Ca ^{0} \rightarrow Ca ^{2+}\]
The 2 bromine atoms are reduced (because they gain electrons)
\[2Br ^{0} \rightarrow 2Br ^{1-}\]

These ions, or the charged atoms, will combine to form your compound.
\[2Br ^{1-}+Ca ^{2+} \rightarrow CaBr _{2}\]