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Predict the ground-state electron configuration of the following ions Ru^2+
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[Kr]4d\(^6\)
If you need the complete electron configuration for the ATOM: \[1s ^{2}2s ^{2}2p ^{6}3s ^{2}3p ^{6}4s ^{2}3d ^{10}4p ^{6}5s ^{2}4d ^{6}\] But, because you have an ion, the atom will lose electrons from its highest energy level first, which is \[5s ^{2}\] Losing the 2 electrons from this level causes the ion to be \[Ru ^{2+}\] and the new complete electron configuration becomes: \[1s ^{2}2s ^{2}2p ^{6}3s ^{2}3p ^{6}4s ^{2}3d ^{10}4p ^{6}4d ^{6}\]
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