Question

PLS HELP!!! MEDAL WILL BE GIVEN OUT!!!

Answer 1

@wolf1728

Answer 2

@Nnesha

Answer 3

@bibby

Answer 4

@leahhhmorgannn

Answer 5

@wes_is_here

Answer 6

@pooja195

Answer 7

@jakyfraze

Answer 8

@Azionne

Answer 9

someone pls help... im in a hurry :/

Answer 10

what do you need help with?

Answer 11

the attachment is all the way in the top :)

Answer 12

@Compassionate please help?

Answer 13

@Whitemonsterbunny17

Answer 14

@blow_pop2000

Answer 15

@rhettwalker14

Answer 16

@rhettwalker13

Answer 17

lol

Answer 18

cmon guys plsss

Answer 19

is that math

Answer 20

yea lol ik i tagged you onpurpose hahah

Answer 21

lol sorry i cant help

Answer 22

do you know anyone who can?

Answer 23

no i dont think so

Answer 24

ugggghhhh seriously ppl.... i need help!!!

Answer 25

ill try

Answer 26

@ChantySquirrel1129** can you help pls?

Answer 27

@Owlcoffee

Answer 28

@MTALHAHASSAN2

Answer 29

@johnweldon1993

Answer 30

@ShadowLegendX

Answer 31

@wwb00

Answer 32

@wwb00

Answer 33

@badmood

Answer 34

@Hero please be are hero and help us

Answer 35

wow 31 min lol

Answer 36

@themazinmathmaster

Answer 37

@ags2658 what in the world are you typing?

Answer 38

fr lol

Answer 39

ughghghghghgghhg

Answer 40

i would help but i am not good at math

Answer 41

duh lol ik your not hahah

Answer 42

wow lol

Answer 43

@Austin6i6

Answer 44

@zpupster

Answer 45

lol rude xD

Answer 46

fr

Answer 47

i think i can figure it out give me a sec

Answer 48

o3o
I suck at math but WOW this looks hard to do

Answer 49

ok thnx :D

Answer 50

it is

Answer 51

xD

Answer 52

I'll try

Answer 53

thnx :)

Answer 54

oh sure try offline lol

Answer 55

lol

Answer 56

hahahahahahahaha

Answer 57

seriously @ags2658 what are you doing? lol

Answer 58

thats what im thinking lol

Answer 59

(6,-5)

Answer 60

OMG!!!! THANK GOD FINALLY SOMEONE ANSWERED!!!!!!

Answer 61

EVERYONE QUICKLY GIVE @Ac3 A MEDAL!!!!

Answer 62

(11,4) will also work

Answer 63

it wasn't that hard lmfao calm down

Answer 64

lol

Answer 65

look at the first parallelogram

Answer 66

OMG YOU DONT UNDERSTAND!!!! LOL IT WAS FOR MEEEEEHHHHHH

Answer 67

FINALLY ANSWERED AFTER A WHOLE HOUR!!!

Answer 68

thxn lol

Answer 69

notice how for the top 2 the y values are the same, same for the bottom 2

Answer 70

therefore for another parallelogram to be similar the y values must be the same hence why (11,4) and (6,-5) work

Answer 71

oooohhhh ok thnx :D

Answer 72

cmon guys dont take forever to medal him lol

Answer 73

your welcome

Answer 74

or her

Answer 75

i'm a guy

Answer 76

ok him lol

Answer 77

need anymore help before i go offline? i'm not online much

Answer 78

im good for now :) how much longer will you be on?

Answer 79

omg are you guys gunna take another hour to give him a medal? lol

Answer 80

I have one more physics problem to do and then i'm gonna knock out so however long that takes me

Answer 81

just tag me if you need help

Answer 82

ok :)

Answer 83

i'll see if i have time to come to the rescue lol

Answer 84

I believe I can help you. :D
First, let's find one of the sides, namely, the sides between the points (-3,5) and (-5,2).
We can use the distance formula to find the side length.
\[Distance=\sqrt{(x _{2}-x _{1})^{2}+ (y _{2}-y _{1})^{2}}\]
Let's plug in the two points I mentioned earlier:
\[\sqrt{((-5)-(-3))^{2} + (2-5)^{2}}\]
Let's simplify this:
\[\sqrt{(-5+3)^{2}+ (-3)^{2}}\]
\[\sqrt{(-2)^{2}+(-3)^{2}}\]
\[\sqrt{4+9}\]
\[\sqrt{13}= 3.60555\]
This is the side length between (-3,5) and (-5,2).
Since the shape is enlarged, we will need the distance of that same side (but bigger). We were given two points outside the parallelogram. They are (0,4) and (-6,-5). We now need to find the distance between them.
Using the Distance formula, we plug in both points:
\[\sqrt{(-6-0)^{2}+ (-5-4)^{2}}\]
We will now simplify it:
\[\sqrt{(-6)^{2}+(-9)^{2}}\]
\[\sqrt{36+81}\]
\[\sqrt{117}=10.81665\]
We now have the length of one side and its enlargement. In order to know the ''length multiplier'' (number that you multiply with side to get enlarged side), we must divide the enlarged side by the smaller side.
\[\frac{ 10.81665 }{ 3.60555}= 3\]
This means that the enlarged parallelogram is THREE times bigger than the original. The top length of the enlarged parallelogram is 12. Take one of the points and move it horizontally by 12 units. The only point that works, by this method, is (6,-5).
I know that I didn't answer first, but I wanted you to understand how to get the answer. This way, you can learn the method and use it at a later time. :D

Answer 85

my jaw just droped hahahahahah

Answer 86

^ tho

Answer 87

ag your overthinking it it's much more simpler than all that

Answer 88

thnx tho @ags2658 :)

Answer 89

I simply wanted to explain how to get the answer. The work looks complicated, but it's easier than that. You find out by how many times the new parallelogram is bigger, find a new side, and use that find a correct point.

Answer 90

You are welcome! :D
I had the answer a while back, but I wanted to show you how I got it...it turns out that someone got it before me. :'(
I hope I helped, though. ^^

Answer 91

baaaiiiiii :D yes it did thnx so much guys :)

Answer 92

No problem! If you ever need help, you can tag me as well and I will help you. :)