PLEASE HELP if gPRIME(x)=2g(x) and g(-1)=1. then g(x)= 1) e^(2x) 2) e^(-x) 3)e^(x+1) 4) e^(2x+2) 5) e^(2x-2) explanation would be greatly appreciated
:) i think checking the options out is the easiest way we know that g(-1)=1 so you check the options put x=-1 in them the the expression which equals 1 is answer When we check option 3 and option 4 are suitable answer But there will only be 1 solution So now we see that whos gPRIME(x) will equal 2g(x) can you do from here? :)
i dont think so, i'm sorry can you assist me
ok :) is it clear that the solution is either 3 or 4?
Yes i understand that, when we plug in -1 into the x the answer is 1 for both
and we already have an example which shows that g(-1)=1
i'm confused what we plug into the derivatives of options three and four to know which one is the answer
ok 1st lets find out the derivative of option 3
2e^(2x+2)
^this is the derivative or gPRIME(x) of the option number 4 :D
oh shoot I apologize I did the wrong one first
e^(x+1)
llol its ok so it is gPRIME(x) of the 4th option g(x)=e^(2x+2) can you find a relation between gPRIME(x) and g(x) :)
yes thats also correct e^(x+1) is correct derivative for 3rd option :)
its mulitplyed by 2....?
yes :D and now read the ques and check if option 4 satisfy all those conditions :)
OH MY GOODNESS that's too cool
yeah B)
thank you very much :)
No problem (B
Join our real-time social learning platform and learn together with your friends!