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Mathematics 14 Online
OpenStudy (anonymous):

PLEASE HELP if gPRIME(x)=2g(x) and g(-1)=1. then g(x)= 1) e^(2x) 2) e^(-x) 3)e^(x+1) 4) e^(2x+2) 5) e^(2x-2) explanation would be greatly appreciated

imqwerty (imqwerty):

:) i think checking the options out is the easiest way we know that g(-1)=1 so you check the options put x=-1 in them the the expression which equals 1 is answer When we check option 3 and option 4 are suitable answer But there will only be 1 solution So now we see that whos gPRIME(x) will equal 2g(x) can you do from here? :)

OpenStudy (anonymous):

i dont think so, i'm sorry can you assist me

imqwerty (imqwerty):

ok :) is it clear that the solution is either 3 or 4?

OpenStudy (anonymous):

Yes i understand that, when we plug in -1 into the x the answer is 1 for both

OpenStudy (anonymous):

and we already have an example which shows that g(-1)=1

OpenStudy (anonymous):

i'm confused what we plug into the derivatives of options three and four to know which one is the answer

imqwerty (imqwerty):

ok 1st lets find out the derivative of option 3

OpenStudy (anonymous):

2e^(2x+2)

imqwerty (imqwerty):

^this is the derivative or gPRIME(x) of the option number 4 :D

OpenStudy (anonymous):

oh shoot I apologize I did the wrong one first

OpenStudy (anonymous):

e^(x+1)

imqwerty (imqwerty):

llol its ok so it is gPRIME(x) of the 4th option g(x)=e^(2x+2) can you find a relation between gPRIME(x) and g(x) :)

imqwerty (imqwerty):

yes thats also correct e^(x+1) is correct derivative for 3rd option :)

OpenStudy (anonymous):

its mulitplyed by 2....?

imqwerty (imqwerty):

yes :D and now read the ques and check if option 4 satisfy all those conditions :)

OpenStudy (anonymous):

OH MY GOODNESS that's too cool

imqwerty (imqwerty):

yeah B)

OpenStudy (anonymous):

thank you very much :)

imqwerty (imqwerty):

No problem (B

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