heelpps(image below)
I got 3/5(X^2+7)
@Owlcoffee
\[\frac{ 6x^2-54x+84 }{ 8x^2-40x+48 } \div \frac{ x^2+x-56 }{ 2x^2+12x-32 }\] Begin by solving the division of fractions, you can also apply the synthetic division on both in order to have a more simplified problem to solve: \[\frac{ 6x^2-54x+84 }{ 8x^2-40x+48 } \times \frac{ 2x^2+12x-32 }{ x^2+x-56 }\] ending with: \[\frac{ (6x^2-54x+84)(2x^2+12x-32) }{ (8x^2-40x+48)(x^2+x-56) }\]
What's left to do is to apply the corresponding simplification and factorization, ending up with the corresponding synthetic division.
What, lol? Don't you find the greatest factor for each, then multiply
No, the multiplication of fractions are just numerator-numerator, denominator-denominator: \[\frac{ a }{ b }\times \frac{ x }{ y } \iff \frac{ ax }{ by }\] If it was the sum of two fractions with different denominator, yes, that would be the case.
I 3(81/2(5)
I got
is it 3(x-2) 2(x-3)
CAn you show me your work?
its on paper, lol
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