Please help!! Which of the following is a polynomial with roots 4, −5, and 7? f(x) = x3 − 6x2 − 27x + 140 f(x) = x3 − 6x2 − 20x + 27 f(x) = x3 − 20x2 − 27x + 35 f(x) = x3 − 20x2 − 35x + 140
\(\large\color{black}{ \displaystyle {\rm~A~polynomial~with~root~}a~{\rm is}:}\) \(\large\color{black}{ \displaystyle f(x)=x-a}\) (A line) Same way, \(\large\color{black}{ \displaystyle {\rm~A~polynomial~with~roots~}a,~{\rm and}~b~{\rm is}:}\) \(\large\color{black}{ \displaystyle f(x)=(x-a)(x-b)}\) AND, same way \(\large\color{black}{ \displaystyle {\rm~A~polynomial~with~roots~}a,~b,~{\rm and}~c~{\rm is}:}\) \(\large\color{black}{ \displaystyle f(x)=(x-a)(x-b)(x-c) }\) And so on
But, these are polynomials "of the least degree" and with "scale factor" of 1.
It seems like your polynomials are indeed least degree polynomial. So just you my first post to find your polynomial.
So how would I get x. Sorry I'm really confused:(
??
How would I start the problem? I read the lesson, but I don't get it
See my first post? Look at the last polynomial with roots a, b, and c. The reason that this works, because my f(x)=0, when evaluated at x=a, b or c. ((Because 0 times anything is zero)) So you just model the same thing, but your a, b, and c are: 4, -5, and 7 (The order doesn't matter)
`STEP 1:` Model the f(x) ((just as I showed, WITH a, b, and c BUT, YOU USE YOUR NUMBERS)) `Step 2` Then, EXPAND your polynomial.
(x-4)(x-4)(x-7)? So then I would expand?
check parenthesis #2, please.
whoops. (x-4)(x-5)(x-7)?
your second zero is NEGATIVE 5.
(\(x-\color{red}{-5}\))=(x+5)
(x-4)(x+5)(x-7)
Yes, then expand :)
So then I'd multiply?
Yes, expand it...
Would it be (x) = x^3 − 20x^2 − 35x + 140
only the +140 and x^3 are correct... NO, it would not.
next time, please show your work.
Ok, what is (x-4)(x+5) ?
(without showing work, I can't tell you where you made the error in expanding)
x^3 − 6x^2 − 27x + 140
Yes, perfect!
I understand now:) Thanks!
Alrighty ... yw
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