Question

sketch the parabola

Answer 1

state the vertex , focus and directrix

Answer 2

\(\large\color{black}{ \displaystyle y=a(x-h)^2+k }\)

\(\large\color{black}{ \displaystyle {\rm Vertex} \quad\quad\quad\quad\quad\quad \left(h,k\right) }\)
\(\large\color{black}{ \displaystyle {\rm Leading~~Coeff.} \quad\quad a }\)

Answer 3

When a>0, parabola opens up
When a<0, parabola opens down

Answer 4

\(\large\color{black}{ \displaystyle y=-12x^2=-12x^2+0=-12(x-0)^2+0 }\)

So,\(\large\color{black}{ \quad\quad\displaystyle h=0 }\)
\(\large\color{black}{ \quad\quad\quad \displaystyle k=0 }\)

Answer 5

vertex is (0,0)
focus : (-3,0)
directrex : x= 3

Answer 6

is it correct?

Answer 7

FOCUS: (h, k + 1/(4a)) = (0, 0 + 1/(4• -12)) = (0, ?)

Answer 8

im confuse

Answer 9

For any parabola
that is in a form of:
\(\large\color{black}{ \displaystyle y=(x-h)^2+k}\)

The focus point
is given by:
\(\large\color{black}{ \displaystyle \left(h,~k+\frac{1}{4a}\right)}\)

Answer 10

oh is that the same as