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How much heat is produced when 2.80 mol of A reacts? 2A + B <=> 2C + 2D Given: Substance Heat of Formation A -225 B -395 C 187 D -507 Step-by-step guide on how to solve this please. Thank you. :)
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Steps for Future Reference: 1. Find the standard enthalpy of reaction using this formula: |dw:1448222041002:dw| you'll get 205 kJ/mol 2. Solve the heat absorbed, since I got 205 kJ/mol heat per 2 mol of A, if I'll have 2.80 mol, I should have 287 kJ: (205/2) x (2.80) = 287 :) You are very much welcome ;)
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