Angela made the trip by bus in 16 hours and the return trip by car in 20 hours. A bus traveled 10 miles per hour faster than the car. How far was the trip? (Use the formula D=rt [Distance = rate x time])
Do you have any idea what to do?
No I don't lol
That's ok! :) We have to set two equations: one for the car and one for the bus.
FOR THE CAR: time: 20 hours rate: x FOR THE BUS: time: 16 hours rate: 10+x \(\text{(since it is 10 mph faster than the car)}\)
we know that d=rt and e have to find the distance.
EQUATION FOR THE CAR: d=20x EQUATION FOR THE BUS: d=16 (10+x)
Are you getting it?
So far yes
Okay cool! So now, equate the two equation since both of them have d=??? So... \(\huge 16(10 + x)=20x\) Now solve for x.
Is it x = 8?
\(\huge 160+16x=20x\)
\(\huge 160=4x\) What is \(160 \div 4\)?
40
Good! So we now know that x=40. Now, substitute it to either of the two equations: EQUATION FOR THE CAR: d=20x EQUATION FOR THE BUS: d=16 (10+x)
800
So the distance is 800. :)
Thank you! Can you help me with another problem lol
I can try lol
It's not a distance problem, it's a percent problem
Forty percent of the signs are circular. If 3600 signs are noncircular, how many signs are there in all?
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