Question

If I wanted to change the y-intercept of the graph from (0,2) to (0,5), what form would you use and what would you do to make the change?

Answer 1

I'm sure there are several ways to look at this situation.
First of all, I need to know whether a graph was part of this problem. The problem statement mentions changing the y-intercept of the graph. (Which graph?)
If you were to use or to find the slope-intercept form of the equation of a straight line, y=mx + b, then that equation would initially look like y=mx+2.
Were you to keep everything except for the y-intercept the same, and to change the y-intercept to (0,5) then the appropriate equation would look like y=mx+5.

Answer 2

There was no graph that came with the problem. My notes didn't say anything about the slope intercept form. My options are standard form, vertex form, and factored form.

Answer 3

Can you write out in symbols what those 3 forms are? I'll keep helping you if you respond (not sure if you're active atm)

Answer 4

Factored form:
y=a(x-r)(x-r)

Vertex form:
y=a(x-h)^2+k

Standard form:
y=ax^2+bx+c

Answer 5

From which of these is it possible to (immediately) tell what value y would be when x is zero? If I told you that x=0, you would immediately be able to tell what value (in terms of symbols) y would be at that point?

Answer 6

Would it be factored form?

Answer 7

So in factored form, can you immediately tell what value y would be when x = 0? I personally can't tell that.

I think the correct answer is your standard form, because when x =0 the terms ax^2+bx cancel to 0, and you are left with just y = c. C would be the value of y when x=0, otherwise known as the....?